Solution steps

2sin(sq)x = sinx
=>2sin(sq)x - sinx = 0
=>sinx(2sinx -1) =0
=>sinx=0 or (2sinx -1) = 0

since(0<= x <= 2(pi))
for sinx=0
x= 0,pi,2(pi)
for sinx = (1/2)
x= pi/6 or (5/6)pi

so x=0, pi/6, pi, (5/6)pi, 2(pi)


plz...let me know how much was I upto the mark...